IAS EXAM PUZZLE QUESTIONS
Only 1% Students solved it (IAS exam)
3+5+6=151872
5+5+6=253094
5+6+7=303585
5+5+3=251573
then 9+4+7=_______?
Time to check your intellect… All the best!
So were you able to solve the riddle? Leave your answers in the comment section below.
SOLUTION OF THIS PUZZLE
The solution to the first 4 digits is pretty straight forward, and I am sure most of you must have easily got it.
It works out to be a+b+c = (a*b)(a*c)??
The last 2 digits are really tough to crack…
Here’s how you do it. Reverse of {(a×b)+(a×c)-c}
So the number would (a×b),(a×c),{(a×b)+(a×c)-c}reverse.
So for 1st one: 3+5+6=151872;
axb = 3×5 = 15; axc = 3×6 = 18;
{(a×b)+(a×c)-c} = ((3×5)+(3×6)-6} = 27
— Reverse of 27 is 72
axb = 3×5 = 15; axc = 3×6 = 18;
{(a×b)+(a×c)-c} = ((3×5)+(3×6)-6} = 27
— Reverse of 27 is 72
So 9+4+7=_______?
axb = 9×4 = 36;
axc = 9×7 = 63;
{(a×b)+(a×c)-c} = ((9×4)+(9×7)-7} = (36+63-7)=92
— Reverse of 92 is 29.
axc = 9×7 = 63;
{(a×b)+(a×c)-c} = ((9×4)+(9×7)-7} = (36+63-7)=92
— Reverse of 92 is 29.
Hence 9+4+7 = 366329
IAS EXAM PUZZLE QUESTIONS
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Oleh
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